Quandaries
and Queries |
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AFB secondary (10-12) student Hello, I received a question on my test and I did not know how to approach the question. My teacher would like us to re-do the questions that we got wrong. Here's the one that I need help in: City A is 30 miles directly north of City C, and City B is 40 miles directly east of City C. Cities A and B are connected by a straight road. Find the length of the shortest path from City C to the road that connects A and B. Hint: The shortest path, segment CD, is the length of the perpendicular from C to segment AB. First, find AB, AD, and BD. I would really appreciate if you will be able to take out the time to help me. Thank you in advance! |
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Hi, Did you draw a diagram?
Since triangle ACB is a right triangle, you can use Pythagoras theorem to show that the road from A to B is 50 miles long. I let x be the number of miles from A to D and y be the number of miles from C to D. Since CD is perpendicular to AB, triangles ACD and DCB are right triangles. Write down Pythagoras theorem for each of these triangles. This gives you two equations in x and y. Solve these equations to find x and y. Penny |