I reproduced the diagram you sent
I divided the lot into three triangles and labeled the vertices.
I am going to find the lengths of the two lines I added using the law of cosines, so I need to express the angle measurements using decimal fractions of degrees so that I can use my calculator to calculate the cosines.
25' is 25/60 = 0.417o and 48' is 48/60 = 0.8o
Thus the measure of angle A is 76.417o and the measure of angle D is 44.8o .
The law of cosines, applied to triangle ABE gives
|BE|2 = |AB2| + |EA|2 - 2|AB||EA| cos(A)
= 3222 + 1132 - 2 322 113 cos( 76.417o )
= 103684 + 12769 - 72772 0.23485
Ant thus |BE| = √ 99362.225 = 315.21 feet.
In a similar fashion I found |EC| = 318.61 feet
Now I can use Heron's formula to calculate the areas of the three triangles.
For example, for triangle ABE let a = 113, b = 322 abd c = 315.21, then
s = (a + b + c)/2 = 375.105 and area = Sqrt[s (s - a)(s - b)(s - c)] = 17683.9 square feet.
Similarly the area of triangle BCE is 2314.31 square feet and the area of triangle CDE is 9854.33 square feet. Thus the area of your lot is
17683.9 + 2314.31 + 9854.33 = 29852.5 square feet.
There are 43560 square feet in an acre so your lot has an area of
29852.5/43560 = 0.69 acres