Quandaries and Queries
Hi! My name is Emma and the level of the question I need help on is middle (I am in 9th grade).
I do not get how to "solve for x". For example:
3x - 5 - (4x - 8) = 2(2 - 3x) + 29
For the above question, I always get confused on what steps to take first, second, third, etc.
I am in regular 9th grade math, and all of my classmates get how to do it and I don't.
You first look inside the parentheses to see if you can do any simplification. Inside the parentheses in this problem are
Neither of these can be simplified so the next step is to perform any multiplications. On the right side you have
On the left side -(4x - 8) can be interpreted as (-1)(4x - 8) so
Thus, so far I have
Now on each side collect the terms with an x in them and collect the terms without an x to get
You want to end up with an expression of the form "x = some number" so you have to get all the terms with an x in them on the left of the equation and all the remaining terms on the right. If I add 6x to both sides I will eliminate the -6x term from the right side
To eliminate the 3 from the left side, add -3 to both sides
Finally divide both sides by 5 to get