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Find the point on the curve y=x2 where the tangent to the curve is parallel to the secant line connecting (-1,1) and (2,4)
Hi,
The line joining (-1,1) and (2,4) has slope
(4 - 1)/(2 - (-1)) = 3/3 = 1
Thus you want the point on the curve where the tangent has slope 1.
Penny
