 |
| ||
| |||
|
| Math Central | Quandaries & Queries |
|
Subject: Algebra with Trigonometry Some tiles are arranged in rows so that the number of tiles in each row is 8 more than the number of rows. The same number of tiles can be arranged in 3 more rows than the first pattern with 16 tiles in each row. |
Hello Ann.
In the first scenario, there are r rows and r+8 tiles per row, so there are r(r+8) tiles in total.
In the second scenario, there are r+3 rows and 16 tiles per row, so there are (r+3)16 tiles in total.
These are equal, so r(r+8) = (r+3)16.
Solve for r, then use that in either the left hand or right hand side above.
Hope this helps,
Stephen La Rocque.
| ||
| ||
| ||
 |
 |
|
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.