We have two solutions for you.

Hi Ben.

The way I would solve this is to first give variable names to the two

things we want to find: the length L and the width W.

The perimeter is 128 so:

128 = L + W + L + W

And the length is 8 more than the width so:

L = W + 8

That last line means that wherever you see L, you can substitute "W + 8". So let's do that in the first equation:

128 = (W + 8) + W + (W + 8) + W

Can you solve it now?

Stephen La Rocque>