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| Math Central | Quandaries & Queries |
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Subject: algebra, math Find three consecutive odd integers such that the sum of the first and second is 27 less than 3 times the third. |
Hi Emma.
You are finding three consecutive odd integers, so let's say the smallest is called a. Then the next one is (a+2) and the third one is (a+4), because they are consecutive odd integers.
Now the sum of the first and second (that's a + (a+2) ) is (equals) 27 less than 3 times the third ( 3(a+4) - 27 ).
So a + (a+2) = 3(a+4) - 27.
Can you solve for a now?
Stephen La Rocque.>
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