Eriona,
I am going to solve a similar but different question.
Solve 7s + 19 = 6
I find that it helps to think of such an equation as a balance, the kind you might see in a physics lab with two pans that balance.
On the left pan is the left side of the equation, 7s + 19 and on the right pan is the right side of the equation,  6. The balance between them is the equal sign. (It might seem strange to have a negative weight, but it's only an analogy.)
The task is to manipulate the weights, always maintaining a balance, to the place where you have s alone one one pan and a number on the other, then you know that s and that number have the same value, that is they are equal.
The balance will be maintained if I add a weight of 19 to both sides. Algebraically this is
7s + 19 =  6 and thus
7s + 19  19 =  6  19
which is
7s =  25
At this point you are almost done. You want s alone on the left side and you have 7 times s. The balance will be maintained if you divide both sides by 7 and hence
7s =  25 and thus
^{7s}/_{7} =  ^{25}/_{7} so
s = 3 ^{4}/_{7}
Now try your equation.
Penny
