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When we asked for clarification Carol sent this drawing
Hi Carol, It looks like you have a pyramid constructed on a base which is a regular hexagon. Look at one of the triangles that form the sides.
Q is the midpoint of one of the sides of the base so angle PQR is a right triangle. Hence you can use Pythagoras' theorem to find the length |PQ|. Now look at the three dimensional pyramid again.
S is at the centre of the hexagonal base so |PS| is the height of the pyramid. Angle PSQ is a right angle so again you can use Pythagoras' theorem to find |PS| if you can first find |SQ|. |SQ| is half the width of the hexagon which you can find using our response to an earlier question. Penny | ||||||||||||
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