



 
Hi Gerry, I am going to reword your question to add some notation.
I made the total distance 2d kilometers because I am assuming it is d kilometers each way. Since distance = time rate I know that on the forward trip
The return trip took f + e hours so on the return trip
Thus the return trip was d/f  d/(f + e) kilometers per hour slower than the forward trip. I hope this helps.  


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