|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Gilbert, I am not sure what you mean by reducing the over all size. If you want the width of the reduced pentagon to be r times the width of the original pentagon (r some fraction smaller than 1) then you accomplish this by multiplying the width, length and height of the peak in the original pentagon by r. If however you want the area of the smaller pentagon to be some factor, say k, of the larger pentagon then yo need to reduce the lengths of the sides by √k. I can illustrate with a simpler example. Suppose you have a rectangle that is x units by y units then its area is xy square units. If you multiply the length of each side by √k then you have a rectangle that is √k x units by √k y units and hence an area of
I hope this helps, | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |