   SEARCH HOME Math Central Quandaries & Queries  Question from Jessica, a student: This is a word problem of Application of Rational Expressions. This is a algebra math. Can't figure it out. I don't know how to solve the problem to get to the answer. Thank You. Solve the problem. Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 224 miles in the same time that Dana travels 204 miles. If Chuck's rate of travel is 5 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel? The answer is : 56 mph Hi Jessica,

The basic fact here is that distance is equal to time times rate. The distance and rate are different for Chuck and Dana so I used

dc = 224 miles, Chuck's distance
dd = 204 miles, Dana's distance
rc = Chuck's rate in mph
rd = Dada's rate in mph
t = time in hours

You are also told that rc= rd + 5

Now write both equations,

dc = t × rc and
dd = t × rd

Substitute the values you know and solve for t.

I hope this helps,
Harley     Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.