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Question from jocelyn, a student:

I wasn't able to solve this equation:

only find the function using Pythagorean theorem
Please help me....

sinA = 3/4 find secB
tanA = 3/4 find cosA
sinB = 4/5 find tan A
cosA = 5 find csc A
b =5; a= 12 find sin A
c =25; a = 24 find cot A
a = 6; c =10 find b?
Find B when c = 25; a = 24
Find A when a = 5 and b = 12
csc = 1/2 find cos

Hi Jocelyn,

By your notation and the fact that you are to use the Pythagorean Theorem only I think you have a right triangle with angles A, B and C where C is the right angle and sides of length a, b and c as in the diagram below.

If this is correct the the Pythagorean Theorem tell us that

a2 + b2 = c2

and hence if you know two of a, b and c you can find the third. For example if a = 9 and c = 15 then

92 + b2 = 152 or 81 + b2 = 225
Hence b2 = 225 - 81 = 144 and thus b = 12.

Similarly if you know the definitions of the trig functions you can solve for the trig functions in your examples. For example if sinA = 12/15 then a = 12 and c = 15. From the calculation above using Pythagoras Theorem you know that b = 12 and thus

secB = c/a = 15/9 = 5/3.

I hope this helps,
Penny

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