



 
Hi Katrina. How many ways can you choose 2 men from among 6? You have six choices for the first man and five for the second, so there are 6 x 5 / 2 = 15 different pairs. You might know the notation 6C2 = 6! / ( 2! x (62) ! ) = 6 x 5 / 2 = 15. Now if the first two men are color blind and the next four are not, there is a 0.09 x 0.09 x 0.91 x 0.91 x 0.91 x 0.91 chance of that. So the answer to your question is the product of all this:
Hope this helps,  


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