



 
Marsia, Think about solving a simple algebraic equation such as
I expect that you would divide both sides by 5 to obtain
But 1/5 is 5^{1} which is the inverse of 5 so you can think about solving
as multiplying both sides by the inverse of 5 to obtain
but 5^{1} × 5 = 1 so
The same technique works with a linear system if you can write it as
and A has an inverse A^{1}. Then A^{1} ×A = I and hence
Penny  


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