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Question from Mike, a student:

The tail of a fish weighs 9 oz. The head weighs as much as the tail and half of the body. The body weighs as much as the head and tail combined. What is the total weight of the fish?

Hi Mike.

Let H = the weight of the head and let B = the weight of the body.

"The tail of a fish weighs 9 oz. The head weighs as much as the tail and half of the body."

H = 9 + (1/2)B

"The body weighs as much as the head and tail combined."

B = H + 9

"What is the total weight of the fish?"

Find B + H + 9.

To solve this, we first eliminate one of the variables (I'll choose B) by substituting it out:

H = 9 + (1/2) (H + 9)

Solve for H. When you have that, you can solve for B and then add B + H + 9 to get the final answer.

Hope this helps,
Stephen La Rocque.

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