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| Math Central | Quandaries & Queries |
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Question from Richter, a student: what is the value of lim [cos (π/x)]/(x-2)? |
Hi Richter,
Since cos (π/2) = 0 you have a limit where the numerator and denominator both approach zero as x approaches 2 and hence you can use l'Hopital's Rule.
d/dx(cos (π/x)) = - [sin(π/x)][- π/(x2)] and
d/dx(x - 2) = 1
Can you see how to complete the problem now?
Harley
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