



 
Hi Ruby, I'll try the orthocentre and you can do the circumcentre. The orthocentre is the place where the three altitudes meet so I drew the triangle and two altitudes.
The line segment AB has slope (3  2)/(5 + 2) = 1/7 and hence the altitude through C has slope 7. The line through C with slope 7 is
The line segment BC has slope (6  2)/(2 + 2) = 2 and hence the altitude through A has slope 1/2. The line through A with slope 1/2 is
I then solved the two equations (1) and (2) and found that x = y = 1. Thus the orthocentre is (1, 1). I hope this helps,  


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