Question for Quandaries and Queries at Math Central
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Subject: math
Name: jordan
Who are you: Student (Secondary)

what is 8+(-2)(-5)/4-(-1)-4(-2+3)

 


Jordan,

Use Bedmas to decide the order of calculating
b=brackets - so do (-2+3) first
e=exponents - none in this question
d=division - do from left to right, and at the same time as multiplication
m=multiplication - do from left to right, and at the same time as division; so next do (-2)x(-5)/4
and 4x(?), where ?=-2+3
a=addition - do from left to right, and at the same time as subtraction
s=subtraction - do from left to right, and at the same time as addition

8+(-2)(-5)/4-(-1)-4(-2+3)
=8+(-2)x(-5)/4-(-1)-4(1)
=8+(10)/4-(-1)-4x(1)
=8+2.5-(-1)-4
=10.5-(-1)-4
=10.5+1-4
=11.5-4
=7.5

Or, if using fractions rather than decimals:

8+(-2)(-5)/4-(-1)-4(-2+3)
=8+(-2)x(-5)/4-(-1)-4(1)
=8+(10)/4-(-1)-4x(1)
=8+5/2-(-1)-4
=16/2 + 5/2 - (-1) - 4
=21/2 - (-1) - 4
=21/2 + 1 - 4
=21/2 + 2/2 - 4
=23/2 - 4
=23/2 - 8/2
=15/2
(note: 15/2 = 7.5)

Paul