Question for Quandaries and Queries at Math Central --------------------------------------------------- Subject: math Name: jordan Who are you: Student (Secondary) what is 8+(-2)(-5)/4-(-1)-4(-2+3) Jordan, Use Bedmas to decide the order of calculating b=brackets - so do (-2+3) first e=exponents - none in this question d=division - do from left to right, and at the same time as multiplication m=multiplication - do from left to right, and at the same time as division; so next do (-2)x(-5)/4 and 4x(?), where ?=-2+3 a=addition - do from left to right, and at the same time as subtraction s=subtraction - do from left to right, and at the same time as addition 8+(-2)(-5)/4-(-1)-4(-2+3) =8+(-2)x(-5)/4-(-1)-4(1) =8+(10)/4-(-1)-4x(1) =8+2.5-(-1)-4 =10.5-(-1)-4 =10.5+1-4 =11.5-4 =7.5 Or, if using fractions rather than decimals: 8+(-2)(-5)/4-(-1)-4(-2+3) =8+(-2)x(-5)/4-(-1)-4(1) =8+(10)/4-(-1)-4x(1) =8+5/2-(-1)-4 =16/2 + 5/2 - (-1) - 4 =21/2 - (-1) - 4 =21/2 + 1 - 4 =21/2 + 2/2 - 4 =23/2 - 4 =23/2 - 8/2 =15/2 (note: 15/2 = 7.5) Paul