Hi Liz ,
I changed the cube to have dimensions 2 by 2 by 2 so that the holes are circular with a radius of 1 unit, that makes the numbers simpler. I put the centre of the cube at the origin with the zaxis is upwards. Drill a hole centered along the xaxis and and a second centered along the yaxis. The orange lines are in the xy plane. (My diagram is not great but I hope you see what I am doing.)
Slice through the cube by a plane parallel to the xy plane, v units above the xy plane (at the the green line). Lift off the piece above the slice and look down from the top. You see
The white parts are removed and only the blue remains. I am not going to show you the details but the lengths of the sides of each of the squares is
1  Sqrt[1  v^{2}] where Sqrt is the square root.
I want to focus on the part of the cube with x, y and z all positive that remains after drilling these two holes. The volume of this solid is
Now drill down from the top. One of two things happen.
If v is small, less than ^{1}/_{√2} then the drill misses the blue part that remains after the first two holes were drilled.
If v is larger than ^{1}/_{√2} then you see
and the orange pieces are removed by the drill.
Let's look more closely at one of these regions.
Let A(v) be the area of the orange bite removed by the drill then
The volume of the region with x, y and z positive that remains after drilling the first two holes and is subsequently removed by drilling the third hole is
Thus the volume that remains after drilling the three holes in my 2 by 2 by 2 cube is
8 (1  √2  ^{3π}/_{4})
Penny
