Subject: sigma notation
Name: marie
Who are you: Student

how do i get this in sigma notation...i only need an explanation
1^2 + (2+3)^2 + (4+5+6)^2 + (7+8+9+10)^2....


Hi Marie,

What I see is that for the nth term you add together n integers and then square the sum. The question is what n integers do you add? Look at the terms before the nth term. The first term uses 1 integer, the second term used 2 integers, the third term uses 3 integers, ..., the (n-1)st term used n-1 integers. Thus in total you have already used

1 + 2 + 3 + ... + (n-1) integers.

For each n let

k(n) = 1 + 2 + ... + (n-1) = n(n-1)/2

The sum that makes up the nth term then starts at k(n) + 1 and hence the nth term is


Does this help?