Subject: Simultaneous equations
Who are you: Other

e^2y-x+2=0
ln(x+3)-2y-1=0

Hi,

I would write the first equation as

e^2y = x - 2

and then take the log of both sides

ln(e^2y) = ln(x - 2 ) or
2y = ln(x - 2)

Substitute this into the second equation to get

ln(x + 3) - ln(x - 2) - 1 = 0

which is

ln((x + 3)/(x - 2)) = 1.

Now take the exponential of both sides to get

(x + 3)/(x - 2) = e¹ = e

Solve for x.

Penny