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Subject: Probability problem 10 balls numbered 1-10 are in a jar. George reaches into the jar and pulls out a ball. Then Wally pulls out another ball. What is the probability that the sum of the two numbers is even? |
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Hi Ryan, To get an even sum, either both would have to select even numbers, or both would have to select odd numbers. Since these events are disjoint, you can use the relationship: P(sum is even) = P(George chooses and even number and Wally chooses an even number) + P(George chooses an odd number and Wally chooses an odd number) Can you take it from here? If not, try a jar with 4 balls numbered 1- 4 and list all the possible outcomes. Haley |
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