 |
| ||
| |||
|
| Math Central | Quandaries & Queries |
|
Question from Arul: Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2 , and 5/8 , respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem ? Thanks for ur help in solving this Arul
|
Hi Arul.
Since they work independently you just multiply the probabilities together Arul.
For example, if I spill my coffee 1 out of 10 mornings, drop my toast 2 out of 25 mornings and miss my bus 1 out of 4 mornings, then what is the probability that on a given morning I will spill my coffee, drop my toast, but catch my bus? It is 1/10 x 2/25 x 3/4 = 6/1000.
Cheers,
Stephen La Rocque.
| ||
| ||
| ||
 |
 |
|
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.