   SEARCH HOME Math Central Quandaries & Queries  Question from Carol, a parent: Hello, I am new at this and very rusty on my math.  I am getting a 24 Ft. round pool and would like to put 2ft width stone (small) edging around it.  How much would I need to buy. I have to buy it by the yard (cubic yard)  I am not looking for an exact, just an approx. even would be great. Thanks Hi Carol.

Cubic yards is a unit of volume. You can calculate the volume of stone you need if you know the area and the depth. You didn't mention the depth, so I'll use 1 inch depth and you can multiply the final answer by the number of inches you really want. Here is a diagram of what you are describing: And below I've drawn the geometric sketch of the surface. If the diameter of the round pool is 24 ft, then its radius is 12 ft. Since the width of the edging is 2 ft, the radius of the circle for the outside of the edging is 2 ft more than the pool's radius. So we have two radii.

We need the area represented as the ring (mathematicians call this an annulus). The area of this ring is just the area of the big circle minus the area of the small circle.

Since the area of a circle is calculated as π r2 , the area of the ring is

A = πR2 - πr2 .

The volume is this area times the depth (d).

V = d ( πR2 - πr2 ).

Before we put actual numbers into the equation, we have to make sure we are using compatible units. Since you ultimately want cubic yards, we should first convert all the measurements to yards:

d = 1 inch = 1/36 yards,
R = 14 ft = 14/3 yards, and
r = 12 ft = 4 yards.

Now we can use these in our calculations. Remember that π is about 3.1416.

V = (1/36) ( π (14/3)2 - π (4)2 )
V = 0.5 cubic yards for each inch of depth

So for every inch of depth, you'll need half a cubic yard.

Hope this helps,
Stephen La Rocque.     Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.