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Hi Cecelia. That sounds like an big aquarium. Based on your measurements, I think this sketch shows the situation: Because the length along the wall is more than twice the distance from the wall to the front, you don't actually have a full semicircle, in which case the calculation would be easier. Instead, this is a chord of a circle with an unknown radius.
The pink lines indicate radii from the three points on the tank to the implied center of the circle at point O. I've also labelled the other interesting spots we'll need to refer to.
The area of a circular sector is ½r2θ where θ is the angle
So we need to find r and θ. Let's draw a more detailed diagram.
This means we know the length of two sides of AC2 = 412 + 362 Since OY bisects AC, then YC = ½(54.58) = 27.26 inches. Also, since we know two sides of
And in As well, r = CO = YC / (cos So we can put these values of r and θ into our equation for the volume:
I see you are writing from Jamaica and I am uncertain whether Jamaicans use liters, US gallons or UK gallons for measuring water volume. Respectively, their conversion factors give:
Stephen La Rocque.> | ||||||||||||
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Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |