



 
Hi Danielle. What is the probability that the first bulb is defective? It is 3 in 8. If that occurs, then there is a 2 in 7 chance the second bulb chosen is defective and a 1 in 6 chance that the third bulb chosen is defective. The chance therefore, that all three happen is (3/8)(2/7)(1/6) which is indeed 1/56. Good thinking!  


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