



 
Hi Ema. The technical name for that kind of algebraic expression is a bivariate polynomial. I'm going to do a similar problem to yours to show you the technique. Factor completely: Solution: 2a^{5}b (2a^{2}b^{2}  5ab  12) Now I can see that what is in the parentheses is in the form of Ax^{2 } + Bx + C, where in this case x = ab and A, B, and C are all constants. So this is actually a normal trinomial like you've solved before. In this case, you have 2x^{2 }  5x  12. Use normal decomposition factoring to break this down. If you aren't sure about that, Penny wrote a good description here. You get (2x + 3)(x  4). Then we can replace x with ab. Since 2a^{2}b^{2}  5ab  12 = (2ab + 3)(ab  4), my final answer is 2a^{5}b(2ab + 3)(ab  4). Hope this helps,  


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