Hi Marina.

I'll show you with a similar question:

Find the equation, is standard form, with all
integers coefficients, of the line perpendicular
to 4x + 10y = 5 and passing through (-2,4).

A perpendicular line is one that has the negative reciprocal slope of the line it is perpendicular to. So I need to know the slope of the line 4x + 10y = 5. To find it, I convert to y=mx+b form:

first line:
4x + 10y = 5
10y = -4x + 5
y = (-2/5)x + 1/2

So the slope of the new line is the negative reciprocal of (-2/5), which is just (5/2). Now I know a point on the new line and the slope of the new line. I can use the following template of a line to finish the equation:

new line:
y - y₀ = m (x - x₀)

I substitute in what I know, then convert to standard form:

y - 4 = (5/2) (x - (-2) )
y - 4 = (5/2)x + 5
(5/2)x - y = -9
5x - 2y = -18.       [Answer]

You can solve your problem the identical way, Marina.

Hope this helps,
Stephen La Rocque.