|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Mike.
Due to similar triangles, corresponding side length ratios are equal: Thus, x + 13 1/4 = 22 1/4, which you had already calculated. Knowing x, we can now calculate the really useful radii r and R by using Pythagorus: So now we know we are cutting from an annulus with inside radius 14 15/16" and outside radius 37". Now we need to consider the portion we must cut. We know the outside circumference we want remaining is the circumference of the larger radius of the truncated cone. That circumference is the circumference of a circle with radius 29 9/16": whereas the circumference of the outside of the annulus pattern is
When we solve for θ we get: and now substitute in our earlier expressions for c and C to find the value of θ
| ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |