



 
Hi Mitch. I cannot give you a list, but I can tell you how it is calculated.
Now you have to apply the Fundamental Counting Principle:
What this means for us is that if there are 10 ways of choosing the first digit and 9 ways of choosing the second digit, then there are 109 ways of choosing the first two digits. It continues: if there are 109 ways of choosing the first pair of digits and 8 ways of choosing the third digit, there are 1098 ways of choosing the first three digits. And so on... 5. So now you multiply the choices together: 10987 to get the number of different four digit sequences where order does matter. To make it unordered, we have find the number or ways a given set of four digits can be rearranged. We use the Fundamental Counting Principle again. The first digit will be one of the four we chose. The second digit will be one of the three that are left, and so on. So there are 4321 ways of ordering a fourdigit number. 6. Finally, we divide the number of "ordered" possibilities by the duplication factor (the number of ways any one group of four digits can be rearranged). So your answer is (10987) / (4321). Hope this helps,  


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