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| Math Central | Quandaries & Queries |
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Name: Patricia Who are you: Student Hello! I am having difficulties involving this problem. can you help me? I have a test tomorrow about this. Can you answer me as soon as possible? Thanks! How long will it take a stone dropped from atop a 1000-meter tall building to reach the ground? Thanks, Patricia. |
Hi Patricia.
The general equation of motion for an object under constant acceleration (like that due to gravity in your question) is this:
d=v0 t+½at2
where d is the displacement (distance), v0 is the initial velocity, a is the constant acceleration and t is the time.
In your case, you know d is 1000 m, v0 is 0 (it is dropped, not thrown), a is the standard for earth's gravity (9.8 m/s2 ) and you want to find t, which will be the time in seconds .
Substitute these into the equation and solve for t.
Hope this helps,
Stephen La Rocque.
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