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Abby, Biker A's speed is 1 lap every 8 minutes, so that is 1/8. When you multiply speed by time, you get distance. So if we let T = the time in minutes when Biker B passes Biker A, then T x 1/8 is Biker A's distance and T x 1/6 is Biker B's distance. When Biker B passes Biker A, she has gone lap further than Biker A. That means Biker A's distance is one less than Biker B's distance. T(1/8) = T(1/6)  1 Solve for T. Cheers,  


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