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| Math Central | Quandaries & Queries |
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Question from alexavier: need all of the 5 digit combinations using the numbers 1-56. |
Alexavier,
The number of ways of choosing k things from n things is n!/[k! (n-k)!] where n! is n × (n-1) × (n-2) × ··· × 2 × 1 so the number of ways of choosing 5 numbers from 56 numbers is 56!/[5! × 51!] = 3,819,816. Far too many to list.
Harley
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