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Amy, You can do it without coordinates if you wish. It's certainly not any easier but here is one way. I modified Stephen's diagram slightly to give the pont of intersection a name P. Let the length of BQ be x ft, the length of QP be y ft and the length of PB be h ft. By Pythagoras theorem x^{2} + y^{2} = h^{2} Using pythagoras theorem on the triangle CBA I found that CB = 300 ft. Also PR = 240  x ft, Harley  


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