



 
Hi Anne, In my diagram C is the centre of the circle and x is the distance from C to A. Since the triangle is isosceles A is the midpoint of the base. let b = AB then b is half the length of the base of the isosceles triangle. From the diagram h = R + x. Triangle ABC is a right triangle so using Pythagoras theorem
Substitute x = h  R and solve for b. The area inside the circle but outside the triangle is
Substitute the value of b you found above and simplify. Two questions:
Penny  


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