



 
we have two responses for you Hi Ash, I didn't see how to factor this so I decided to try the general quadratic. This involves the root of b^{2}  4ac which I calculated to be
so the only solution is b/2a = (6 +2 i)/2 = 3 + i. Now that you know the answer it's easy to check. Expand [z  (3 + i)]^{2} and check that you get Penny
Hi Ash. Try completing the square by taking the c term to the other side and using half the b term: You have z^{2} + bz + c = 0, so to complete the square ( z + b/2 )^{2} = c + (b/2)^{2}. Thus [ z  (3+i) ]^{2} =  (8+6i) + (3 + i)^{2} Solve for z. Stephen La Rocque.  


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 