Hi,

I am going to illustrate how to solve this using the example

Solve 3v - 4(2 + v) = -3(2v + 1)

The first step is to multiply through the parentheses on both sides. On the left

-4(2 + v) = -4 × 2 + (-4)×v = -8 - 4v

Using he same procedure on the right and collecting like terms I get

3v - 4(2 + v) = -3(2v + 1)
3v - 8 - 4v = -6v - 3
-v - 8 = -6v - 3

To collect all the terms involving v on the left side add 6v to each side

-v - 8 + 6v = -6v - 3 + 6v
5v - 8 = -3

Finally add 8 to each side

5v - 8 + 8 = -3 + 8
5v = 5

Thus v = 1.

You should now substitute v = 1 in the original expression 3v - 4(2 + v) = -3(2v + 1) to check if v = 1 is the correct solution.

Now try v-4(4-v) = -2(2v-1).

Penny