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Hi Charles, If f(x) = axb ln(x) then
If there is a critical value at x = e3 then f '(e3) = 0. This allows you to find b. Also x = e3 is the only critical value of f(x) (Why?) and hence the maximum value you are given must occur ar x = e3. Set f(e3) = 1/2 e and solve for a. Harley | ||||||||||||
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