



 
Hi Conor, If the second equation were just 5y = 4x you could add the equations and get
and solve for x. Unfortunately the second equation is 3y = 4, but with a little care you can use the same technique. Look at your equations again
If you multiple both sides of the first equation by 3 and both sides of the second equation by 5 then the y term in the first equation becomes 15y and the y term in the second equation becomes 15y. Now you can add the two equations and the y terms cancel. So here is my solution.
Penny  


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