



 
Hi, I'm glad that you don't have a problem solving this because, in my opinion the algebraic approach isn't needed. My preferred approach is to use 24 marshmallows and 76 toothpicks. A marshmallow is a head and a toothpick is a leg. Put 2 toothpicks in each marshmallow and you have constructed 24 chickens but you have 76  28 = 28 toothpicks left over, that is 14 pairs of toothpicks. With each of these pairs of legs you can turn a chicken into a cow. Thus you are left with 14 cows and 24  14 = 10 chickens. If you want to use algebra you can let h be the number of chickens and c be the number of cows. Each animal has 1 head so
Each chicken has 2 legs and each cow has 4 legs so
Solve for h and c. Harley  


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