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Thus dV/dt = dh/dt cubic meters per minute. I hope this helps,
Hi David. If it is rectangular (and oriented conventionally, with a flat side on the bottom) then the depth of the water doesn't matter: the water level will rise at a constant rate for a constant flow rate. So if you start from empty and fill the trough, the water level will rise in 1 minute. What's the volume of the trough? That divided by 1 minute is the flow rate you need. This question doesn't actually require any differentiation at all! Cheers,  


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