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| Math Central | Quandaries & Queries |
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Question from davontay, a teacher: 9(d+5)=3(d-3)+6d |
Davontay,
Are you sure you have written this equation correctly? Simplified the equation becomes
9(d + 5) = 3(d - 3) + 6d
9d + 45 = 3d - 9 + 6d
9d + 45 = 9d - 9
Subtracting 9d from each side gives
45 = -9
This is impossible so the conclusion is that there is no number d so that 9(d+5)=3(d-3)+6d.
Harley
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