



 
Hi Don, Here is how I am interpreting your question. Please let me know if my interpretation is incorrect. You have a 32 foot frontage, (A to B in my diagram) and a circular arc from A to B that is backset 2 feet at the midpoint of the frontage, D in my diagram. I let C be the centre of the circle and called its radius r feet. ADC is a right triangle with AD = 16 feet and DC = r  2 feet and hence using Pythagoras theorem
Thus
and hence
If the angle BCA is measured in radians then the length of the arc from A to B is
I can find the angle DCA which is half of the angle BCA because tan(DCA) = AD/DC = 16/63 = 0.2540. Thus angle DCA = tan^{1}(0.2540) = 0.2487 radians and angle BCA = 2 × 0.2487 = 0.4974 radians. Hence
Harley In August 2009 Don sent us these photos of the veterans memorial wall  


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 