



 
Hi Frank. Pythagoras' Theorem says that a^{2} + b^{2} = h^{2} for any right triangle where h is the length of the hypotenuse and a and b are the lengths of the legs. For a square with a diagonal drawn through it, h is the diagonal and a and b are the legs. In a square of course, a = b, so you
where a is the length of the side of the square and h is the diagonal length. Now you can solve for the length a (because that is what you want to know):
If you know the length h (you said it is 2 to the one half power, which is the same as sqrt(2)) then you can just substitute that value in for h to find the value of a:
So the answer is simply 1 unit. Cheers,  


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