|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Glen. You will need to assume that the water submerses the Wood's metal entirely to solve this question. You will also need to know the density of the Wood's metal (look in your reference book; I think it is around 10 g/cm3). Use the density to find the volume of the Wood's metal (volume = mass / density). Then just subtract the volume of the Wood's metal from the new water level volume to find the original volume. Remember, 1 cm3 = 1 mL. Cheers, | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |