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| Math Central | Quandaries & Queries |
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Question from jack: i'm looking for the square footage of a tank that is 10'diameter x 23'high,floor,ceiling and walls |
Hi Jack,
You can think of the tank as being constructed from three pieces, two circular disks that form the floor and ceiling and a rectangle that is rolled to form the wall. Since the diameter is 10 feet the radius r is 10/2 = 5 feet. The area of a circular disk is π r2 so each disk has an area of π × 52 = 78.54 square feet.
The length of the rectangle is the circumference of the circle which is 2 π r = 31.41 feet. Thus the area of the rectangle is 23 × 31.41 = 722.57 square feet. Thus the total surface area is
2 × 78.54 + 722.57 = 879.6 square feet.
Penny
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