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The principal is the same when working in other bases. Let's say we have 453_{6} (we use subscripts to denote the base) and we want to convert to base 11. The original base here is called "6" if we agree to always write the base itself in base 10. This is the usual practice, but it is important to remember that the base is really always 10 when written in the base itself. What I mean is that 10_{6} = 6_{10}. 453_{6} is composed of three digits each in its place, so expressed in expanded base 6 notation this is:
Now we convert these small numbers directly from base 6 to base 11 and substitute them in:
Let's leave the exponents as is, since 0, 1, 2 are all smaller than both bases anyway. So the substitution gives us this:
It really helps to write the multiplication table for 6_{11} in base 11 if you cannot do it in your head. I'll solve this in steps:
And finally we just add in base 11:
You'll notice that I had to ensure I was "carrying" on elevens instead of tens, but that is just working in base 11, so we haven't really used base 10 through this whole conversion. However, I want to check my work in base 10:
Now you try this approach with your base 6 to 12 conversion, Jade. Cheers,
Jade, Here is another technique that is similar to the method I would use to put 177 in base 6. Suppose you have 177 hockey pucks and you want to express this number in base 6. Arrange the pucks in stacks of 6 pucks each. You get 29 stacks of 6 pucks each with 3 left over. Now arrange the 29 stacks of 6 pucks into groups of 6 stacks each. You get 4 groups of 6 stacks each and 5 stacks of six pucks left over. Thus you have
That's is 4 × 6^{2} + 5 × 6 + 3 = 453_{6} pucks. Arithmetically what is did was
Read the remainders from bottom to top to get 453_{6}. Now suppose you want to convert 453_{6} to base eleven. I can use the same technique, repeatedly divide by eleven and record the remainder. The main difference is that you have to express eleven in base 6 and divide in base 6. Eleven is 15_{6} so here is my calculation (without the details)
Thus 453_{6} = 151_{11} Penny  


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