



 
Hi James. You can't directly solve for x. Here's what you can do: First, recognize that ln(2) is a small positive number. Second, recognize that ln(x) in the equation means that the domain is restricted to x > 0, because you can't take the logarithm of a nonpositive number. Look carefully at a graph of y = ln(x) and y = x. For what positive value(s) of x is ln(x) greater than x? Cheers,  


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