Hi Jennifer,

I'm going to look at (x³√y)^1/4.

To put this in exponential form I need to use two properties of exponents

(a × b)^p = a^p × b^p and
(a^p)^q = a^p×q

I also need to know that √a = a^1/2.

Here we go

(x³√y)^1/4 = (x³y^1/2)^1/4

Using the first property this can be written

(x³)^1/4 × (y^1/2)^1/4

and the second property gives

x^3×(1/4) × y^(1/2)×(1/4) = x^3/4 y^1/8

Now try your problem,
Penny